(1/2)^2x+1=64

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Solution for (1/2)^2x+1=64 equation: 



(1/2)^2x+1=64

We move all terms to the left:

(1/2)^2x+1-(64)=0



Domain of the equation: 2)^2x!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

(+1/2)^2x+1-64=0

We add all the numbers together, and all the variables

(+1/2)^2x-63=0

We multiply all the terms by the denominator


(+1-63*2)^2x=0

We add all the numbers together, and all the variables

(-125)^2x=0

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